A closed loop $PQRS$ carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments $PS, SR$ and $RQ$ are $F_1, F_2$ and $F_3$ respectively and are in the plane of the paper and along the directions shown, the force on the segment $QP$ is
AIPMT 2008, Medium
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${F_{4} \sin \theta=F_{2}} $
${F_{4} \cos \theta=\left(F_{3}-F_{1}\right)}$
$\therefore F_{4}=\sqrt{\left(F_{3}-F_{1}\right)^{2}+F_{2}^{2}}$
For a closed loop there is no translation.
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