A coin is placed on a disc. The coefficient of friction between the coin and the disc is $\mu$. If the distance of the coin from the center of the disc is $r$, the maximum angular velocity which can be given to the disc, so that the coin does not slip away, is:
JEE MAIN 2024, Difficult
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$\mathrm{N}=\mathrm{mg}$
$\mathrm{f}=\mathrm{m} \omega^2 \mathrm{r}$
$\mathrm{f}=\mu \mathrm{N}$
$\mu \mathrm{mg}=\mathrm{mr} \omega^2$
$\omega=\sqrt{\frac{\mu g}{r}}$
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