A conductor in the form of a right angle $ABC$ with $AB = 3\, cm$ and $BC = 4\, cm$ carries a current of $10\, A$. There is a uniform magnetic field of $5\, T$ perpendicular to the plane of the conductor. The force on the conductor will be......$N$
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(c) According to the question figure can be drawn as shown below.
Force on the conductor $ABC$ $=$ Force on the conductor $AC$
$= 5 \times 10 \times (5 \times 10^{-2}) = 2.5\, N$
Force on the conductor $ABC$ $=$ Force on the conductor $AC$
$= 5 \times 10 \times (5 \times 10^{-2}) = 2.5\, N$
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