A cylinder of $5$ litre capacity, filled with air at $N.T.P.$ is connected with another evacuated cylinder of $30$ litres of capacity. The resultant air pressure in both the cylinders will be ...... $cm$ of $Hg$
A$38.85$
B$21.85$
C$10.85$
D$14.85$
Medium
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C$10.85$
c Boyle's law states that $P_{1} V_{1}=P_{2} V_{2}$
Here, at $NTP$, pressure $=76 cm$ of $Hg = P _{1}$
$V _{1}=5 L$
$V _{2}=30 L +5 L$
Now
$P _{1} \times(5)= P _{2} \times(35)$
$P _{1}=7 P _{2}$
$P _{2}=76 / 7=10.8 cm$ of $Hg$
So, pressure in both cylender $=10.8 cm$
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