A cylindrical tube of uniform cross-sectional area $A$ is fitted with two air tight frictionless pistons. The pistons are connected to each other by a metallic wire. Initially the pressure of the gas is $P_0$ and temperature is $T_0$, atmospheric pressure is also $P_0$. Now the temperature of the gas is increased to $2T_0$, the tension in the wire will be
A$2{P_0}A$
B${P_0}A$
C$\frac{{{P_0}A}}{2}$
D$4{P_0}A$
Medium
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B${P_0}A$
b (b)Volume of the gas is constant $V = $ constant
$P \propto T$
i.e., pressure will be doubled if temperature is doubled
$P = 2{P_0}$
Now let F be the tension in the wire. Then equilibrium of any one piston gives
$F = (P - {P_0})A = (2{P_0} - {P_0})A = {P_0}A$
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