A galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6\,mA$. It can be used as a voltmeter to measure a maximum of $6\, V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers
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(c) $R = \frac{V}{{{i_g}}} - G = \frac{6}{{6 \times {{10}^{ - 3}}}} - 25 = 975\,\Omega $(In series).
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