${\frac{I}{5} \times G=\frac{4}{5} I \times 4} $
${G=16\, \Omega}$
When additional shunt of $4\, \Omega$ used
${\rm{I'}} \times 16 = 2({\rm{I}} - {\rm{I'}})$
$16{\rm{I}} = 2{\rm{I}} - 2{\rm{I'}}$
$18{\rm{I'}} = 2{\rm{I}}$
${\rm{I'}} = \frac{{\rm{I}}}{9}$


