A horizontal force of $129.4 \,N $ is applied on a $10\, kg$ block which rests on a horizontal surface. If the coefficient of friction is $0.3$, the acceleration should be ....... $m/s^2$
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(b) From the relation $F - \mu mg = ma$

$a = \frac{{F - \mu mg}}{m} = \frac{{129.4 - 0.3 \times 10 \times 9.8}}{{10}} = 10\;m/{s^2}$

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