A horizontal force of $40\,N$ is applied to a $5\, kg$ block which is at rest on the horizontal surface. If the coefficient of kinetic friction is $0.4$, then the acceleration of the block is ........ $m/s^2$ $(g = 10 \,m/s^2)$
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$\mathrm{f}=\mu \mathrm{mg}=0.4 \times 5 \times 10=20 \mathrm{N}$
$\Rightarrow a=\frac{F-f}{m}=\frac{40-20}{5}=4 m / s^{2}$
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