A jet of water with cross section of $6$ $cm^2$ strikes a wall at an angle of $60^o $ to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is $12$ $m/s$, the force acting on the wall is ....... $N$
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$F=\frac{d P}{d t}$
$=\frac{2 d m V \cos 60^{\circ}}{d t}$
$=\frac{2(\rho A d x) V \cos 60^{\circ}}{d t}$
$=2 \rho A V^{2} \cos 60^{\circ}$
$=10^{3} \times 6 \times 10^{-4} \times 12^{2}$
$=86.4 \;N$
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