A long straight wire carrying current of 30,A is placed in an external uniform magnetic field of induction 4 times 10^{-4} T. The magnetic field

Q: A long straight wire carrying current of $30\,A$ is placed in an external uniform magnetic field of induction $4 \times 10^{-4}$ $T$. The magnetic field is acting parallel to the direction of current. The magnitude of the resultant magnetic induction in tesla at a point $2.0\, cm$ away from the wire is

c (c) ${B_1} = 4 \times {10^{ - 4}}\,T$ ${B_2} = {10^{ - 7}} \times \frac{{2 \times 30}}{{2 \times {{10}^{ - 2}}}}$$ = 3 \times {10^{ - 4}}\,T$ ${B_{{\rm{net}}}} = \sqrt {B_1^2 + B_2^2} $$ = 5 \times {10^{ - 4}}\,T$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A long straight wire carrying current of $30\,A$ is placed in an external uniform magnetic field of induction $4 \times 10^{-4}$ $T$. The magnetic field is acting parallel to the direction of current. The magnitude of the resultant magnetic induction in tesla at a point $2.0\, cm$ away from the wire is

A$10^{-4}$
B$3 \times 10^{-4}$
C$5 \times 10^{-4}$
D$6 \times 10^{-4}$

Medium

STD 11 Science
NEET
STD 12 - 4. Moving charges and magnetism
Physics

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