A non-planar loop of conducting wire carrying a current $I$ is placed as shown in the figure. Each of the straight sections of the loop is of length $2a$. The magnetic field due to this loop at the point $P$ $(a,0,a)$ points in the direction
d (d) The magnetic field at $P(a,\,0,\,a)$ due to the loop is equal to the vector sum of the magnetic fields produced by loops $ABCDA$ and $AFEBA$ as shown in the figure.
Magnetic field due to loop $ABCDA$ will be along $\hat i$ and due to loop $AFEBA$, along $\hat k$. Magnitude of magnetic field due to both the loops will be equal. Therefore, direction of resultant magnetic field at $P$ will be $\frac{1}{{\sqrt 2 }}(\hat i + \hat k)$.
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