A parallel plate capacitor has potential $20\,kV$ and capacitance $2\times10^{-4}\,\mu F$. If area of plate is $0.01\,m^2$ and distance between the plates is $2\,mm$ then find dielectric constant of medium
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$\mathrm{C}=\frac{\varepsilon_{0} \varepsilon_{\mathrm{r}} \mathrm{A}}{\mathrm{d}}$
$\Rightarrow \varepsilon_{\mathrm{r}}=\frac{\mathrm{Cd}}{\varepsilon_{0} \mathrm{A}}=\frac{2 \times 10^{-10} \times 2 \times 10^{-3}}{8.85 \times 10^{-12} \times 0.01}=4.52$
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