Four capacitors of capacitance $10\,mF$ and a battery of $200\,V$ are arranged as shown. How much charge will flow through $AB$ after the switch $S$ is closed .....$\mu C$
Medium
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When switch is open $=\mathrm{C}_{\mathrm{eq}}=\frac{15}{2}\, \mu \mathrm{F}$
$\mathrm{q}_{\mathrm{i}}=\mathrm{C}_{\mathrm{eq}} \mathrm{V}=\frac{15}{2} \times 200=1500\, \mu \mathrm{C}$
When switch is closed
$\mathrm{C}_{\mathrm{eq}}=30\, \mu \mathrm{F}$
$\mathrm{q}_{\mathrm{f}}=30 \times 200=6000\, \mu \mathrm{C}$
$=4.5 \times 10^{-3} \mathrm{\,C}$
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