Two condensers of capacities $1\,\mu F$ and $2\,\mu F$ are connected in series and the system is charged to $120\;volts$. Then the $P.D.$ on $1\,\mu F$ capacitor (in $volts$) will be
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(c) Charges developed are same so ${C_1}{V_1} = {C_2}{V_2}$ $==>$ $\frac{{{V_1}}}{{{V_2}}} = 2$
${V_1} + {V_2} = 120$ $==>$ ${V_1} = 80\,volts$
${V_1} + {V_2} = 120$ $==>$ ${V_1} = 80\,volts$
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