MCQ
A particle is moving with constant acceleration $'a'.$ Following graph shows $v^{2}$ versus $x$ (displacement) plot. The acceleration of the particle is $......{m} / {s}^{2}$
- A$100$
- B$20$
- C$14$
- ✓$1$
✓
Answer
Correct option: D.
$1$
d
${y}={m} {x}+{C}$
${y}={m} {x}+{C}$
${v}^{2}=\frac{20}{10} {x}+20$
${v}^{2}=2 {x}+20$
$2 {v} \frac{{d} {v}}{{d} {x}}=2$
$\therefore {a}={v} \frac{{d} {v}}{{d} {x}}=1$
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