A particle moves such that its acceleration $a$ is given by $a = - bx$, where $x$ is the displacement from equilibrium position and b is a constant. The period of oscillation is
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(b) In the given case, $\frac{{Displacement}}{{Acceleration}} = \frac{1}{b}$
ime period $T = 2\pi \sqrt {\frac{{Displacement}}{{Acceleration}}} = \frac{{2\pi }}{{\sqrt b }}$
ime period $T = 2\pi \sqrt {\frac{{Displacement}}{{Acceleration}}} = \frac{{2\pi }}{{\sqrt b }}$
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