MCQ
A particle moving along the $X-$axis executes simple harmonic motion, then the force acting on it is given by
Where $A$ and $K$ are positive constants
- ✓$-A Kx$
- B$A cos (Kx)$
- C$A exp (-Kx)$
- D$A Kx $
Where $A$ and $K$ are positive constants
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$\overrightarrow{\mathrm{E}}_{1}=\mathrm{E}_{0} \hat{\mathrm{j}} \cos (\omega \mathrm{t}-\mathrm{kx})$ and
$\overrightarrow{\mathrm{E}}_{2}=\mathrm{E}_{0} \hat{\mathrm{k}} \cos (\omega \mathrm{t}-\mathrm{ky})$
At $t=0,$ a particle of charge $q$ is at origin with a velocity $\overrightarrow{\mathrm{v}}=0.8 \mathrm{c} \hat{\mathrm{j}}$ ($c$ is the speed of light in vacuum). The instantaneous force experienced by the particle is