Distance travelled by body \(A\) in \({5^{th}}\)sec and distance travelled by body \(B\) in \({3^{rd}}\) sec. of its motion are equal.
\(0 + \frac{{{a_1}}}{2}(2 \times 5 - 1) = 0 + \frac{{{a_2}}}{2}[2 \times 3 - 1]\)
\(9{a_1} = 5{a_2} \Rightarrow \frac{{{a_1}}}{{{a_2}}} = \frac{5}{9}\)