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When the spring is stretched and released, the wire AB will execute simple harmonic (sinusoidal) motion, so induced emf will vary periodically. At t = 0, wire is at the extreme position. $\text{v}=0.$ $\text{v}=\text{A}\omega\sin\omega\text{t}$ Induced emf $\varepsilon = \text{Bvl}$ $=\text{BA}\omega\text{l}\sin\omega\text{t}$ Where A = BB′= AA′ is the amplitude of motion and ω is angular frequency.
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