Question
A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. Find the emf induced:
  1. In the loop abc.
  2. In the segment bc.
  3. In the segment ac.
  4. In the segment ab.

Answer


  1. Zero as the components of ab are exactly opposite to that of bc. So they cancel each other. Because velocity should be perpendicular to the length.
  2. e = Bv × l
= Bv(bc) + ve at C
  1. e = 0 as the velocity is not perpendicular to the length.
  2. e = Bv(bc) positive at ‘a’.
i.e. the component of ‘ab’ along the perpendicular direction.

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