A rod of length l rotates with a small but uniform angular velocity $\omega$ about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the centre of the rod and an end is:
View full solution →- $\text{zero}$
- $\frac{1}{8}\omega\text{Bl}^2$
- $\frac{1}{2}\omega\text{Bl}^2$
- $\text{B}\omega\text{l}^2$







