A rubber ball is taken to a $100\, m$ deep lake and its volume changes by $0.1\%$. The bulk modulus of rubber is nearly
Medium
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$\beta=\frac{\Delta \mathrm{P}}{\left(\frac{-\Delta \mathrm{V}}{\mathrm{V}}\right)}=\frac{\mathrm{h} \rho \mathrm{g}}{\frac{-\Delta \mathrm{V}}{\mathrm{V}}}=\frac{100 \times 10^{3} \times 10}{10^{-3}}=10^{9} \mathrm{N} / \mathrm{m}^{2}$
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