A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration $3 ms ^{-2}$ is
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(a)
$t \propto \frac{1}{\sqrt{9.8}}, t ^{\prime} \propto \frac{1}{\sqrt{12.8}}$
$\left(\because g ^{\prime}=9.8+3=12.8\right)$
$\therefore \frac{ t ^{\prime}}{ t }=\sqrt{\frac{9.8}{12.8}} \Rightarrow t ^{\prime}=\sqrt{\frac{9.8}{12.8}} t$
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