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STD 11 - 6. system of particles and rotational motion — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 6. system of particles and rotational motion4 Marks
MCQ
A solid sphere rolls down an inclined plane and its velocity at the bottom is $v_1$. Then same sphere slides down the plane (without friction) and let its velocity at the bottom be $v_2$. Which of the following relation is correct 
  • A
    $v_1=v_2 $
  • B
    ${v_1} = \frac{5}{7}{v_2}$
  • C
    ${v_1} = \frac{7}{5}{v_2}$  
  • ✓
    None of these
✓

Answer

Correct option: D.
None of these
d
When solid sphere rolls down an inclined plane the velocity at bottom ${v_1} = \sqrt {\frac{{10}}{7}gh} $

but, if there is no friction then it slides on inclined plane and the velocity at bottom ${v_2} = \sqrt {2gh} $

$\therefore \frac{{{v_1}}}{{{v_2}}} = \sqrt {\frac{5}{7}} $.

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