MCQ
A sound wave of frequency $\nu$ travels horizontally to the right. It is reflected from a large vertical plane surface moving to the left with a speed $v.$ The speed of sound in the medium is $c,$ then
  • A
    The frequency of the reflected wave is $\frac{{\nu (c + v)}}{{c - v}}$
  • B
    The wavelength of the reflected wave is $\frac{{c(c - v)}}{{\nu (c + v)}}$
  • C
    The number of waves striking the surface per second is $\frac{{\nu (c + v)}}{c}$
  • All of the above.

Answer

Correct option: D.
All of the above.
d
(d) Number of waves striking the surface per second (or the frequency of the waves reaching surface of the moving target )

$n' = \frac{{(c + v)}}{\lambda }$$ = \frac{{\nu (c + v)}}{c}$

Now these waves are reflected by the moving target

(Which now act as a source). Therefore apparent frequency of reflected second $n'' = \left( {\frac{c}{{c - v}}} \right)n'$ $ = \nu \left( {\frac{{c + v}}{{c - v}}} \right)$

The wavelength of reflected wave  $n = \left( {\frac{c}{{c - v}}} \right)n'$

The number of beats heard by stationary listener  $ = n'' - \nu  = \nu \left( {\frac{{c + v}}{{c - v}}} \right) - \nu  = \frac{{2\nu v}}{{(c - v)}}$

Hence option $(a)\, (b)$ and $(c)$ are correct.

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