A square loop of area $25\,cm ^2$ has a resistance of $10\,\Omega$. The loop is placed in uniform magnetic field of magnitude $40.0 T$. The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in $1.0 sec$, will be $..........\times 10^{-3}$
JEE MAIN 2023, Diffcult
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$\ell=50\,cm$
$t =1\,sec$
$\therefore V =\frac{0.05}{1}=0.05\,m / s$
$i =\frac{40 \times 0.05 \times 0.05}{10}=0.01\,A$
$F = B { i } l=40 \times 0.01 \times 0.05$
$F =0.02\,N$
$\therefore \quad W =0.02 \times l=0.02 \times .05$
$\therefore \quad W =1 \times 10^{-3}\,J$
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