A transverse wave of amplitude 0.5 , m and wavelength 1 , m and f… - Vidyadip

MCQ

A transverse wave of amplitude $0.5\, m$ and wavelength $1\, m$ and frequency $2\, Hz$ is propagating in a string in the negative $x-$direction. The expression for this wave is

A
$y(x,\,t) = 0.5\sin (2\pi x - 4\pi t)$
✓
$y(x,\,t) = 0.5\cos (2\pi x + 4\pi t)$
C
$y(x,\,t) = 0.5\sin (\pi x - 2\pi t)$
D
$y(x,\,t) = 0.5\cos (2\pi x + 2\pi t)$

✓

Answer

Correct option: B.

$y(x,\,t) = 0.5\cos (2\pi x + 4\pi t)$

b
(b) $y = a\cos \left( {\frac{{2\pi }}{\lambda }vt + \frac{{2\pi x}}{\lambda }} \right) = 0.5\cos \left( {4\pi t + 2\pi x} \right)$

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