A uniform electric field of $20\, N/C$ exists along the $x$ -axis in a space. The potential difference $(V_B -V_A)$ for the point $A(4\,m, 2\,m)$ and $B(6\,m, 5\,m)$ is.....$V$
A$20 \sqrt {13}$
B$-40$
C$+ 40$
D$-20 \sqrt {13}$
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B$-40$
b Potential goes on decreasing in the direction of electric field.
$\therefore (V_B -V_A) = -Edx = -20 \times 2 = -40\, volt$
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