A uniform magnetic field $\vec B = \left( {3\hat i + 4\hat j + \hat k} \right)$ exists in region of space. A semicircular wire of radius $1\,m$ carrying current $1\,A$ having its centre at $(2, 2, 0)$ is placed in $x-y$ plane as shown in figure. The force on semicircular wire will be
b $F = i\left( {\vec l \times \vec B} \right)$ where $\vec l = \sqrt 2 \left( {\hat i + \hat j} \right)$
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A metal ring of radius $r = 0.5 \,\,m $ with its plane normal to a uniform magnetic field $B$ of induction $0.2 T$ carries a current $I = 100\,\, A$. The tension in newtons developed in the ring is:
Two long straight parallel conductors separated by a distance of $0.5\,m$ carry currents of $5\,A$ and $8\,A$ in the same direction. The force per unit length experienced by each other is
A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\,cm$. The magnetic field set up at the centre of the coil is ($\mu_0 = 4\pi \times 10^{-7} weber/amp-metre$)
Two long and parallel wires are at a distance of $0.1\, m$ and a current of $5\, A$ is flowing in each of these wires. The force per unit length due to these wires will be
A current of $1\,A$ is flowing on the sides of an equilateral triangle of side $4.5\times10^{-2}\,m$ . The magnetic field at the centre of the triangle will be
Current $I$ is flowing along the path $ABCDA$ consisting of four edges of a cube (figure $-a$), produces a magnetic field $B_0$ at the centre of the cube. Find the magnetic field $B$ produced at the center of the cube by a current $I$ flowing along the path of the six edges $ABCGHEA$ (figure $b$)