c
(c) Total resistance of the circuit \( = \frac{{80}}{2} + 20 = 60\,\Omega \)
\( \Rightarrow \) Main current \(i = \frac{2}{{60}} = \frac{1}{{30}}A\)
Combination of voltmeter and \(80\) \(\Omega\) resistance is connected in series with \(20\) \(\Omega\), so current through \(20\) \(\Omega\) and this combination will be same \( = \frac{1}{{30}}A\).
Since the resistance of voltmeter is also \(80\) \(\Omega\), so this current is equally distributed in \(80\) \(\Omega\) resistance and voltmeter (i.e.\(\frac{1}{{60}}A\) through each)
\(P.D.\) across \(80\) \(\Omega\) resistance \( = \frac{1}{{60}} \times 80 = 1.33\,V\)