At same value of load
\(A\) has less elongation than \(B \quad \ldots (1)\)
\(\frac{F L}{A Y}=\Delta L\) \(\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { - Load is also taken same }\end{array}\right\}\)
So \(\frac{1}{Y} \propto \Delta L \quad \ldots (2)\)
Using conditions \((1)\) and \((2)\)
We can say
\(Y_A > Y_B\) \(\{\) Young's modulus of \(A\) greater than \(B\}\)
$(\alpha = {10^{ - 5}}/^\circ C$ and $Y = {10^{11}}\,N/{m^2})$