$AB$ and $CD$ are long straight conductor, distance $d$ apart, carrying a current $I$. The magnetic field at the midpoint of $BC$ is
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(b) The field at the midpoint of $BC$ due to $AB$ is $\left( { - \frac{{{\mu _0}}}{{4\pi }}.\frac{i}{{d/2}}\hat k} \right)$ and the same is due to $CD$. Therefore the total field is $\left[ { - \left( {\frac{{{\mu _0}i}}{{\pi d}}} \right)\,\hat k} \right]$
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