According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is :-
A$\frac{9}{2} R$
B$\frac{5}{2} R$
C$\frac{3}{2} R$
D$\frac{7}{2} R$
JEE MAIN 2023, Easy
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D$\frac{7}{2} R$
d Diatomic gas molecules have three translational degree of freedom, two rotational degree of freedom and it is given that it has one vibrational mode so there are two additional degree of freedom corresponding to one vibrational mode, so total degree of freedom $=7$
$C _{ V }=\frac{ fR }{2}=\frac{7 R }{2}$
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