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One mole of an ideal gas is contained with in a cylinder by a frictionless piston and is initially at temperature $T$. The pressure of the gas is kept constant while it is heated and its volume doubles. If $R$ is molar gas constant, the work done by the gas in increasing its volume is
An ideal gas is taken through a quasi-static process described by $P = \alpha\, V^2$, with $\alpha = 5\,atm/m^6$. The gas is expanded to twice its original volume of $1\,m^3$. How much work is done by the expanding gas in this process
A thermo-dynamical system is changed from state $({P_1},\,{V_1})$ to $({P_2},\,{V_2})$ by two different process. The quantity which will remain same will be
A monatornic gas at a pressure $P,$ having a volume $V$ expands isothermally to a volume $2\, V$ and then adiabatically to a volume $16\, V.$ The final pressure of the gas is $(\,Take \,\gamma = 5/3)$
A gas is enclosed in a cylinder with a movable frictionless piston. Its initikl thermodynamic state at pressure $P_i=10^5 \mathrm{~Pa}$ and volume $V_i=10^{-3} \mathrm{~m}^3$ chanıes to i final state at $P_f=(1 / 32) \times 10^5 \mathrm{~Pa}$ and $V_f=8 \times 10^{-3} \mathrm{~m}^3$ in an adiabatic quasi-static process, such that $P^3 V^5=$ constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at $P$, followed by an isochoric (isovolumetric) process at volume $V_f$. The amount of heat supplied to the system in the two-step process is approximately
A diatomic gas with rigid molecules does $10\, J$ of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process ..... $J$.