An ideal gas is taken through the cycle $A \to B \to C \to A$ , as shown in the figure. If the net heat supplied to the gas in the cycle is $5\ J$, the work done by the gas in the process $C \to A$ is .... $J$
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$\mathrm{dR}=\mathrm{dU}+\mathrm{d} \mathrm{W}$
$5=0+10(2-1)+0+\mathrm{W}_{\mathrm{CA}}$
$\mathrm{W}_{\mathrm{CA}}=5-10$
$=-5$ Joule
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