An object 1cm tall is placed 30cm in front of a convex mirror of focal length 20cm. Find the size and position of the image formed by the convex mirror.
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$h_1=1 cm, u =-30 cm, f =20 cm, h _2=?, v =?$
$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}+\frac{1}{-30}=\frac{1}{20}$
$\frac{1}{\text{v}}=\frac{1}{30}+\frac{1}{20}$
$\text{v}=12\text{cm}$
The image is formed 12cm behind the mirror.$\text{m}=-\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\text{m}=-\frac{12}{-30}=\frac{\text{h}_2}{14}$
${\text{h}_2}=0.4\text{cm}$
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When an object is placed at a distance of 15cm from a concave mirror, its image is formed at 10cm in front of the mirror. Calculate the focal length of the mirror.
List two possible ways in which a concave mirror can produce a magnified image of an object placed in front of it. State the difference, if any, between these two images.
Describe with the help of a diagram, the nature, size and position of the image formed when an object is placed beyond the centre of curvature of a concave mirror.