An object 20cm from a spherical mirror gives rise to a virtual image 15cm behind the mirror. Determine the magnification of the image and the type of mirror used.
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Given, The distance of the object 'u' = -20cm Distance of the virtual image 'v' = 15cm We have to find the magnification 'm'. Using the magnification formula, we get We konw that$\text{m}=-\frac{\text{v}}{\text{u}}=-\frac{15}{(-20)}=0.75$
Thus, the image is virtual, erect and smaller in size. The mirror used here is convex, as it forms a smaller virtual image.
Thus, the image is virtual, erect and smaller in size. The mirror used here is convex, as it forms a smaller virtual image.
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