$Assertion :$ For a particle performing $SHM$, its speed decreases as it goes away from the mean position.
$Reason :$ In $SHM$, the acceleration is always opposite to the velocity of the particle.
$Reason :$ In $SHM$, the acceleration is always opposite to the velocity of the particle.
AIIMS 2009, Easy
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Speed $= \omega \sqrt {A^2 - x^2}$ as $| x |$ increases $\Rightarrow $ speed decreases Acceleration is in direction of speed as it comes towards mean position.
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