Assertion : If three capacitors of capacitances $C_1 < C_2 < C_3$ are connected in parallel then their equivalent capacitance $C_P > C_S$.
Reason : $\frac{1}{{{C_p}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \frac{1}{{{C_3}}}$
AIIMS 2002, Easy
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If three capacitors are joined in parallel then their equivalent capacitor will be less than the least value of capacitor so
$C_p > C_s$
$\frac{1}{{{C_p}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \frac{1}{{{C_3}}}$ is incorrect.
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