a
The conditions given are in $NTP$.
At $NTP$,
Pressure, $P=1 \; atm =101325 Pa$
Temperature, $T=20^{\circ} C =\left(20+273.15^{-}\right) K =293.15 K$
Volume given, $V=1$ litre $=10^{-3} m ^{3}$
mass, $m=1.293 gm$
USe equation, $P V=m R T$
$(101325)\left(10^{-3}\right)$
$=(1.293) \cdot R \cdot(293.15)$
$R=0.2673 \; J / K - gm$