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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions3 Marks
Question
Balance the following equations by the oxidation number method.
$\text{MnO}_2+\text{C}_2\text{O}^{2-}_4\xrightarrow{ \ \ \ \ \ \ \ }\text{Mn}^{2+}+\text{CO}_2$
✓

Answer

$\stackrel{+4 \ \ \ \ \ \ \ \ \ }{\text{MnO}}_2+\stackrel{+3 \ \ \ \ \ \ \ \ \ \ \ }{\text{C}_2\text{O}^{2-}_4}\xrightarrow{ \ \ \ \ \ \ \ \ }\stackrel{+2 \ \ \ \ \ \ \ \ \ }{\text{Mn}^{2+}}+\stackrel{+4 \ \ \ \ \ }{\text{CO}}_2$
Total increase in O.N. = 1 × 2 = 2
Total decrease in O.N. = 2
To equalize O.N. multiply $\text{CO}_2$ by 2.
$\text{MnO}_2+\text{C}_2\text{O}^{2-}_4\xrightarrow{ \ \ \ \ \ \ \ \ }\text{Mn}^{2+}+2\text{CO}_2$
Balance H and O by adding $2 \mathrm{H}_2 \mathrm{O}$ on right side, and $4 \mathrm{H}^{+}$on left side of equation.
$\text{MnO}_2+\text{C}_2\text{O}^{2-}_4+4\text{H}^+\xrightarrow{ \ \ \ \ \ \ \ \ \ }\text{Mn}^{2+}+2\text{CO}_2+2\text{H}_2\text{O}$

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