d
According to Arrhenius equation

\( k=A e^{-E_{2} / R T} \)

\( k_{1} =A e^{-E_{\mathrm{A} 1} / R T} \quad (1)\)

\(k_{2} =A e^{-E_{22} / R T} \quad (2)\)

Dividing Eq. \(( 2 )\) by Eq. \(( 1 )\), we get

\(\frac{k_{2}}{k_{1}}=e^{\left(\frac{E_{21}-E_{22}}{R T}\right)}\)

Taking natural logarithm of both sides, we get

\(\ln \left(\frac{k_{2}}{k_{1}}\right) =\frac{E_{\mathrm{al}}-E_{\mathrm{a} 2}}{R T} \)

\(=\frac{10,000}{8.314 \times 300}=4\)