d
Calculate \(E_{cell}^o\) corresponding to each compound under golng disproportlonation reactlon. The reaction for which \(\mathrm{E}_{\text {cell }}^{\circ}\) comes out \(+ve\) is spontaneous.

\(\mathrm{HBrO} \longrightarrow \mathrm{Br}_{2} \quad \mathrm{E}^{\circ}=1.595,\) SRP (cathode)

\(\mathrm{HBrO} \longrightarrow \mathrm{BrO}_{3}^{-} \quad \mathrm{E}^{\circ}=-1.5 \mathrm{V},\) SOP (Anode)

\(2 \mathrm{HBrO} \longrightarrow \mathrm{Br}_{2}+\mathrm{BrO}_{3}^{-}\)

\(\mathrm{E}_{\text {cell }}^{\circ}=\mathrm{SRP}(\text { cathode })-\mathrm{SRP}(\text { Anode })\)

\(=1.595-1.5\)

\(=0.095 \mathrm{V}\)

\(\mathrm{E}_{\text {cell }}^{\circ}>0 \Rightarrow \Delta \mathrm{G}^{\circ}<0\) [spontaneous]