Moles of \({H}_{2} {O}=\frac{72}{18}=4\)
Moles of \({C}_{4} {H}_{10}\) used \(=\frac{1}{5} \times 4\)
Weight of \({C}_{4} {H}_{10}\) used \(=\frac{4}{5} \times 58\)
\(=46.4\, {gm} \Rightarrow 464 \times 10^{-1}\, {gm}\)
[આણ્વિય દળ $: {Na}=23.0, {O}=16.0, {H}=1.0]$
$CaC_2 + H_2O → Ca(OH)_2 + C_2H_2$