Question
Calculate the oxidation number of Cr in $\text{K}_2\text{Cr}_2\text{O}_7$ and S in $\text{S}_2\text{O}_3^{2-}$

Answer

$\text{K}_2\text{Cr}_2\text{O}_7$
$+2+2\text{x}-14=0$
$\text{x}=+6$
$\text{S}_2\text{O}_3^{2-} $
$2\text{x}-6=-2$
$2\text{x}=4$
$\text{x}=+2$

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