Choose the correct answer from the given four options : While com… - Vidyadip

MCQ

Choose the correct answer from the given four options : While computing mean of grouped data, we assume that the frequencies are :

A
Evenly distributed over all the classes.
B
Centred at the classmarks of the classes.
✓
Centred at the upper limits of the classes.
D
Centred at the lower limits of the classes.

✓

Answer

Correct option: C.

Centred at the upper limits of the classes.

In computing the mean of grouped data, the frequencies are centred at the class marks of the classes.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Stastics→Stastics — all question types→Maths STD 10 question papers→CBSE Board STD 10 question papers→CBSE Board question paper generator→

Similar questions

If $\text{P}\Big(\frac{\text{a}}{2},4\Big )$ is the mid $-$ point of the line-segment joining the point $(-6, 5)$ and $B(- 2, 3),$ then the value of a is :

For a symmetrical frequency distribution, we have

If $\text{x}=\text{a}\sec\theta\cos\phi,\text{y}=\text{b}\sec\theta\sin\phi\text{ and z}=\text{c}\tan\theta,$ then $\frac{\text{x}^2}{\text{a}^2}+\frac{\text{y}^2}{\text{b}^2}=$

For a frequency distribution, mean, median and mode are connected by the relation:

A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is:

The zeroes of the quadratic polynomial $x^2+99 x+127$ are :

The zeros of the polynomial $4\text{x}^2+5\sqrt2\text{x}-3$ are :

Choose the correct option and give justification. In Fig., if $TP$ and $TQ$ are the two tangents to a circle with centre $O$ so that $\angle POQ = 110^\circ ,$ then $\angle PTQ$ is equal to :

In Fig $2,$ a circle touches the side $DF$ of $\angle\text{EDF}$ at hand touches $ED$ and $EF$ produced at $K$ and $M$ respectively. If $EK = 9\ cm,$ then the perimeter of $\triangle\text{EDF}\ ($in $\ cm)$ is :

The probability that a number selected at random from the numbers 1, 2, 3, ....., 15 is a multiple of 4, is: