$\therefore \text { Unpaired } e ^{-}=5$
$\mu=\sqrt{ n ( n +2)}$
$=\sqrt{5(5+2)}$
$\mu=\sqrt{35}=5.92 \text { B.M. }$
${\left[ Fe ( CN )_6\right]^{-3}}$
Pairing occur due to strong field ligand $CN ^{-}$
$\therefore$ Unpaired $e^-$ $\Rightarrow 1$
$\mu=\sqrt{ n ( n +2)}$
$=\sqrt{1(1+2)}=\sqrt{3}=1.732 \text { B.M. }$
${\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+},}$
${\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}}$
$(I)\, K_4 [Fe(CN)_6]$ $(II)\, K_3[Cr(CN)_6]$ $(III)\, K_3 [Co(CN)_6]$ $(IV)\, K_2[Ni(CN)_4]$
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