Consider the diagram shown below. A voltmeter of resistance $150\,\Omega$ is connected across $A$ and $B$. The potential drop across $B$ and $C$ measured by voltmeter is $...........\,V$
AIIMS 2015, Diffcult
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(c)

When a voltmeter of resistance $150\,\Omega$ is connected across $A$ and $B$, the resistance across $A$ and $B$ will be

$R _{ ab }=\frac{150 \times 100}{150+100}=60\,\Omega$

Now the equivalent resistance of the circuit will be $R_{a c}=R_{a b}+R_{b c}=60+100=$ $160\,\Omega$

The current in the circuit will be $I=50 / 160=0.31\,A$

Thus, Potential drop across B and C will be $V _{ bc }= IR _{ bc }=(0.31)(100)=31\,V$

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