Download App

2. inverse trigonometric function — ગણિત ધોરણ 12 સાયન્સ — Question

Gujarat Boardગુજરાતી માધ્યમધોરણ 12 સાયન્સગણિત2. inverse trigonometric function1 Mark
MCQ
${\cos ^{ - 1}}\left( {\cos \frac{{5\pi }}{3}} \right) + {\sin ^{ - 1}}\left( {\cos \frac{{5\pi }}{3}} \right) =\ ..... . .$
  • ✓
    $\frac{\pi }{2}$
  • B
    $\frac{{5\pi }}{3}$
  • C
    $\frac{{10\pi }}{3}$
  • D
    $0$
✓

Answer

Correct option: A.
$\frac{\pi }{2}$
${\cos ^{ - 1}}\left[ {\cos \frac{{5\pi }}{3}} \right] + {\sin ^{ - 1}}\left[ {\frac{{\cos 5\pi }}{3}} \right] = \frac{\pi }{2}\ (\because$ ${\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \frac{\pi }{2}).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from 2. inverse trigonometric function→2. inverse trigonometric function — all question types→ગણિત ધોરણ 12 સાયન્સ question papers→Gujarat Board ધોરણ 12 સાયન્સ question papers→Gujarat Board question paper generator→

Similar questions

વક્રો $x^{2}=4b(y+b),b\in R$ ના સમૂહ નું વિકલ સમીકરણ $.......$ છે.
→
$\int {\frac{{{{\sec }^2}x}}{{\log {{(\tan x)}^{\tan x}}}}dx = } $
→
રેખાઓ $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ અને $\frac{x-3}{1}=\frac{y-k}{1}=\frac{z}{1}$ છેદે છે તો $k$ ની પૂર્ણાંક કિંમતોની સંખ્યા $.......$ છે.
→
$f : R -\left\{\frac{-2}{3}\right\} \rightarrow R -\left\{\frac{2}{3}\right\} f( x )=\frac{2 x +3}{3 x +2}$ માટે $f^{-1}( x )=\ ...........$
→
ગણ  $A= \{a, b, c\}$ પરના બે સંબંધ $R_1 = \{(c, a) (b, b) , (a, c), (c,c), (b, c), (a, a)\}$ અને $R_2 = \{(a, b), (b, a), (c, c), (c,a), (a, a), (b, b), (a, c)\}$ હોય તો . . . 
→
Box $I$ contains $30$ cards numbered $1$ to $30$ and Box $II$ contains $20$ cards numbered $31$ to $50 .$ A box is selected at random and a card is drawn from it. The number on the card is found to be a non-prime number. The probability that the card was drawn from Box $I$ is
→
Let $9$ distinct balls be distributed among $4$ boxes, $B_{1}, B_{2}, B_{3}$ and $B_{4}$. If the probability that $B_{3}$ contains exactly $3$ balls is $k\left(\frac{3}{4}\right)^{9}$ then $\mathrm{k}$ lies in the set:
→
વિધેય $L(x) = \int_1^x {\frac{{dt}}{t}} $ એ . . . . સમીકરણનું સમાધાન કરે.
→
ધારો કે  $y=y(x)$ એ વિકલ સમીકરણ $(x+1) y^{\prime}-y=e^{3 x}(x+1)^{2}$, $y(0)=\frac{1}{3}$ નો ઉકેલ છે. તો વક્ર $y = y ( x )$ માટે, $x=-\frac{4}{3}$ એ ...............
→
$\int_{\,0}^{\,\pi } {\log {{\sin }^2}x\,dx = } $
→